Net Force and Angle Problem: Find Solution!

AI Thread Summary
The discussion revolves around a physics problem involving four masses positioned at the corners of a rectangle, specifically focusing on calculating the net force acting on a 2.0kg mass. The user expresses difficulty in solving the problem despite consulting a textbook and seeking help. Participants are encouraged to share their attempts to identify where the misunderstanding may lie. The problem requires calculating both the magnitude and direction of the net force, with specific parameters given for the distances involved. Clear guidance and collaborative problem-solving are emphasized to aid in finding the solution.
FishieKissie06
Messages
6
Reaction score
0
I can't seem to figure our this problem. I went by the book and asked for someone else's help but i still can't figure this out. HELP! :confused:


Four masses are positioned at the corners of a rectangle.

1.0kg-------x----------2.0kg
l l
l l y
l l
4.0kg------------------3.0kg

a) find the magnitude and direction of the net force acting on the 2.0kg mass if x=.20m and y=.12m
_________N
_________degrees counterclockwise from the x-axis, which points to the right
 
Physics news on Phys.org
Please show us your attempt at the problem so that we can see where you lack or went wrong.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top