Net Force on Top Block: 115.2 N

AI Thread Summary
The problem involves calculating the net force on a top block with a mass of 36 kg, accelerated upwards at 3.2 m/s². To find the net force, the formula FNet = m a is applied, resulting in FNet = 36 kg * 3.2 m/s², which equals 115.2 N. The forces acting on the top block include the upward force from the middle block and the downward gravitational force. A free body diagram is recommended for visualizing the forces involved. The correct answer to the net force on the top block is 115.2 N.
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Three blocks are bring accelerated upwards at 3.2m/s2, by a force applied to the bottom block as shown in the figure. The mass of the bottom block is 12kg, the mass of the middle block is 24 kg, and the top block is 36 kg. What is the net force on the top block?

a.44.8 N
b.67.2 N
c.115.2 N
d.240.0 N

I don't know how to start this problem. Do I just do F=(36)(3.2) and get C as my answer?
 
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You're correct. The best way to handle this type of problem is to draw a picture (free body diagram) of the top block.

The top block has two forces acting on it.
Force 1: The middle block is forcing the top block upward.
Force 2: Gravity is pulling the top block downward.

The summation of forces in the vertical direction gives:
FSecond Block - FGravity = FNet

In many problems, you would be given the force of the Second Block and calculate gravitational force to find net force as shown in the equation above. Because we've been given the mass of the top block along with it's acceleration we can calculate the net force directly and forget the above equation:
FNet = m a = (36) (3.2 m/s2) = 115.2 N
 
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