What is the arrangement of net gravitational force on a particle labeled m?

AI Thread Summary
The discussion revolves around determining the arrangement of net gravitational forces on a particle labeled m based on distances from other masses. The initial proposed order of forces is A, B, D, C, but some participants suggest an alternative order of A, D, B, C. A key point made is that in configuration B, the gravitational force is stronger due to one mass being at a closer distance compared to configuration D, where the distance involves a square root calculation. The participant struggles with the math involved, particularly in comparing the distances and their effects on gravitational force. Clarification on the calculations and the reasoning behind the force comparisons is requested.
duoshock
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Hi,

I attached a diagram... to find out the arrangement of the magnitude of the net gravitational force on the particle labeled m from the smallest to the biggest.

my answer is A B D C, anyone had a different way of looking at it?
could you explain? some of my friends said it was A D B C... =|

Thanks in advance
duoshock
 

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In B, there is one mass at distance d, the other at distance D.
In D, there is one mass at distance d, the other at distance \sqrt{d^2+ D^2}.

The force from the mass at distance D will be greater than the force from the mass a distance \sqrt{d^2+ D^2} so the net force in B is greater than in D.
 
i give D a value of 50 and d a value of 1 and my result is square root of (d^2 + D^2) is more than D. My maths isn't very good. Could you help to explain?

Thanks
 
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