Net Resistance of Parallel Circuits: Solve It Now!

  • Thread starter Thread starter kllindsey
  • Start date Start date
  • Tags Tags
    Circuits Parallel
AI Thread Summary
To determine the net resistance of 100 ohms, 250 ohms, and 400 ohms in parallel, the formula used is 1/Rp = 1/100 + 1/250 + 1/400. The calculations yield 1/Rp = 60 + 24 + 15/6000 ohms, resulting in Rp = 61 ohms. The confusion arises from understanding how to manipulate the fractions to find a common denominator. Both the calculated answer and the book's answer are effectively the same, despite differences in presentation. Mastering the arithmetic involved is essential for clarity in solving parallel circuit resistance problems.
kllindsey
Messages
2
Reaction score
0
Question: Determine the net resistance of 100 ohms, 250 ohms and 400 ohms connected in a parallel.

I have no clue how to figure this out. I have read and reread the section in my book and it is not helping. Please help.
 
Physics news on Phys.org
Well what have you tried so far?
 
1/Rp = 1/100 + 1/250 + 1/400

I know the answer is:

1/Rp = 60 + 24 + 15/6000 ohms
Rp = 6000 ohms/99 = 61 ohms

I just have no clue where these numbers are coming from!
 
Well I haven't a clue how you got from your formula to your second line.

I agree that your answer of 61 is close enough though.

Can you not do the arithemetic involved in your first line?
 
Your answer and the books answer are the same. They just multiply the fractions so there is a common denominator (However odd that denominator is)
 
I think it's easist first to watch a short vidio clip I find these videos very relaxing to watch .. I got to thinking is this being done in the most efficient way? The sand has to be suspended in the water to move it to the outlet ... The faster the water , the more turbulance and the sand stays suspended, so it seems to me the rule of thumb is the hose be aimed towards the outlet at all times .. Many times the workers hit the sand directly which will greatly reduce the water...
Back
Top