Net torque question? Block 1 and block 2 hanging on pulley?

AI Thread Summary
In the discussion regarding the net torque on a pulley system with two blocks, the focus is on understanding why only the tensions in the cords are considered for calculating net torque, rather than the weights of the blocks. The reasoning provided emphasizes that the pulley only responds to the forces exerted by the strings, not the masses themselves. The gravitational forces acting on the blocks will be addressed later through free-body diagrams. Additionally, it is clarified that the indices on the masses should be applied to "m" and not "g," as "g" is a constant. This approach is essential for solving more complex problems in mechanics.
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In Fig. 10.45, block 1 has mass m1=460g, block 2 has mass m2=500g, and the
pulley, which is mounted on a horizontal axle with negligible friction ahs radius
R=5.0cm. When released from rest, block 2 falls 75.0cm in 5.00 s without the
cord slipping on the pulley.

(e) What is its rotational inertia?

problem and picture on page 2 problem #55

http://faculty.kfupm.edu.sa/PHYS/marzoug/Phys101/chapter 10 problmes.pdf




Ʃτ = (T2 - T1) R

Why doesn't mg1 or mg2 get calculated into the net torque and only the tensions?



thanks!
 
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Why doesn't mg1 or mg2 get calculated into the net torque and only the tensions?
That happens later - there are three free-body diagrams.
It's good discipline for more complicated problems: the pulley knows nothing about the masses - all it feels is these strings pulling on it.
Note - the 1 and the 2 belong on the "m"'s not the "g"'s ... g is a constant.
 
Simon Bridge said:
That happens later - there are three free-body diagrams.
It's good discipline for more complicated problems: the pulley knows nothing about the masses - all it feels is these strings pulling on it.
Note - the 1 and the 2 belong on the "m"'s not the "g"'s ... g is a constant.

thanks!
 
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