New at using a multimeter, why isn't this working?

  • Thread starter Thread starter Xyius
  • Start date Start date
  • Tags Tags
    Multimeter
AI Thread Summary
The user is trying to measure voltage from a wall outlet using a multimeter but initially receives a reading of zero. They confirm they are using the correct settings for measuring 120V AC in the US and are aware of safety precautions. A question is raised about whether something needs to be plugged into the other socket for the multimeter to function properly. The user later resolves the issue and successfully gets the multimeter to work. Proper usage of the multimeter is essential for accurate voltage readings.
Xyius
Messages
501
Reaction score
4
I am attempting to measure the voltage from my wall outlet. I know all the proper precautions when using the multimeter for measuring voltage from a wall outlet, problem is, when I put the leads into the sockets, my multi meter is reading zero. I have it set to 200V AC (I am in the US so this is sufficient for the standard 120.) Do I need to have something plugged into the other socket? Why is it zero? Thanks a lot.

~Matt
 
Physics news on Phys.org
Nevermind I got it to work
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top