New to the forums, trouble with an integral

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Hello all, I am new to these forums. I'm having trouble with a problem on homework. It seems simple but it is giving me problems.

It is an indefinite integral: Integral of (Sin(2x))/(Sinx)dx

Is there a way to use substitution? Help is appreciated.
 
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\int\frac{\sin{2x}}{\sin x}dx

Use the trig identity.

\sin{2x}=2\sin x \cos x
 
Use the identity:

sin(2x) = 2sin(x)cos(x)
 
roco, that is correct. Obviously a newb, I have no idea how you did that. I'm sure there are stickies somewhere that I need to read.
 
Alright, wow that is simple when you now the identities. Guess i should get to learning those lol thanks awvvu
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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