stunner5000pt
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COnsider a large horizontal frictionless area on the Earth at phi degrees northern latitude. Through an impulse a particle is set in motion with velocity v and then left to move freely ignore all forms of friction. Find the period in the uniformcircular motion of the particle
velocity v = \omega r
v_{x} = v cos \phi
v_{y} = v sin \phi
v_{z} = 0
not sure about the z part...
period T = \frac {2 \pi }{\omega sin \phi}
sin phi because the Y axis the one about which this motion is going about..
I am off by a factor of 2 the answer is T = \frac{\pi}{\omega sin \phi}
velocity v = \omega r
v_{x} = v cos \phi
v_{y} = v sin \phi
v_{z} = 0
not sure about the z part...
period T = \frac {2 \pi }{\omega sin \phi}
sin phi because the Y axis the one about which this motion is going about..
I am off by a factor of 2 the answer is T = \frac{\pi}{\omega sin \phi}