How Is the Period of Uniform Circular Motion Affected by Latitude?

AI Thread Summary
The discussion centers on the effects of latitude on the period of uniform circular motion for a particle moving on a frictionless surface. The particle's velocity is expressed in terms of its components, with the period derived as T = 2π/(ω sin φ), where φ is the latitude. A correction is noted, indicating the correct period formula is T = π/(ω sin φ). The focus is on the motion's dependence on the sine of latitude, emphasizing the role of the Y-axis in this context. The conversation stresses adherence to the textbook source for clarity and accuracy.
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COnsider a large horizontal frictionless area on the Earth at phi degrees northern latitude. Through an impulse a particle is set in motion with velocity v and then left to move freely ignore all forms of friction. Find the period in the uniformcircular motion of the particle

velocity v = \omega r
v_{x} = v cos \phi
v_{y} = v sin \phi
v_{z} = 0
not sure about the z part...

period T = \frac {2 \pi }{\omega sin \phi}
sin phi because the Y axis the one about which this motion is going about..

I am off by a factor of 2 the answer is T = \frac{\pi}{\omega sin \phi}
 
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