Kolahal Bhattacharya said:A rectangular block of mass M1 rests on the frictionless horizontal plane.On it there is a rectanglar shaped hole, drilled from upper surface.A mass M2 is on the frictionless upper surface of the block being connected through string over a pulley another mass M3 which hangs in the hole.The mass M1 is given a horizontal force F.For what value of F, M2 and M3 does not move at all?
The force F for balanced masses M2, M3 on block M1 refers to the net force acting on block M1 when it is in equilibrium. This means that the forces acting on the block are balanced, resulting in no acceleration.
The force F can be calculated using the equation F = M1a, where M1 is the mass of block M1 and a is the acceleration, which is equal to 0 in this case since the block is in equilibrium.
The relationship between the masses M2, M3 and the force F is that they are directly proportional. This means that as the masses M2 and M3 increase, the force F also increases, and vice versa.
If one of the masses M2 or M3 is removed, the force F will decrease accordingly to maintain equilibrium. This is because the remaining mass will have a smaller force acting on it, resulting in a smaller net force on block M1.
No, the force F cannot be greater than the combined masses M2 and M3. This is because in equilibrium, the forces acting on the block must be balanced, meaning that the force F must be equal to the combined weight of the masses M2 and M3.