Newtonian particle problem with air resistance

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Homework Help Overview

The problem involves a particle released from rest that falls under gravity with air resistance proportional to the cube of its velocity. The original poster seeks to find the relationship between velocity (v) and falling distance (y) while grappling with the complexities of the integral involved.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to solve an integral related to the motion of the particle but encounters difficulties with complexity. Some participants suggest factoring techniques and the use of standard integral tables, while others propose using partial fraction decomposition to simplify the integration process.

Discussion Status

Participants are actively discussing various methods to approach the integral, with some providing suggestions on how to manipulate the equation. The original poster expresses uncertainty about the integration process and the correct interpretation of the problem, indicating a productive exploration of ideas without reaching a consensus.

Contextual Notes

The original poster notes a desire to solve the problem independently and acknowledges a misunderstanding regarding the relationship they were initially attempting to find (v vs. t instead of v vs. y). This highlights the importance of carefully interpreting the problem statement.

RawrSpoon
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Hey guys, first time poster but I'm a physics major and probably going to stick around for a while to help people or get some help myself :P

Anyway, on to the problem!

Homework Statement


A particle is released from rest and falls under the influence of gravity. Find the relationship between v and falling distance y when the air resistance is equal to γv3


Homework Equations


F=ma=-mg+γv3


The Attempt at a Solution


I've been able to solve this same problem for γv and γv2 but I can't seem to find an easy way to find
∫dv/(-g+v3)=t+C without Mathematica giving me an incredibly complex answer.

I don't want hand-outs, I want to solve this myself, but I don't have any idea where to go with this. Any tips on what I should be looking at to attempt a solution?
 
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A difference of cubes will factor. So you might want to define a constant b so that you can write your denominator as v^3 - b^3.
 
I'm unsure how that would work? Should I define b as being the cube root of mg so I end up having

m*dv/(v^3-b^3)? I'm not sure how I would integrate from there.
 
That integral is available in standard tables (e.g. CRC). It's messy but it's a closed-form expression. Have you tried to apply it to your integral? BTW in your integral the coefficient for v3 should be γ/m, not that that's a show-stopper. Also, I would choose y > 0 for t > 0 (just a sign change).

The problem doesn't ask for v(t), it just asks for the relationship between v and t. So I would argue that t(v) is an acceptable answer. Try it on for size anyway! :-)
 
RawrSpoon said:
I'm unsure how that would work? Should I define b as being the cube root of mg so I end up having

m*dv/(v^3-b^3)? I'm not sure how I would integrate from there.

Use partial fraction decomposition. You can decompose a fraction of the form [itex]\frac{1}{(x-a)(x-b)(x-c)}[/itex] as a sum of linear fractions [itex]\frac{A}{x-a}+ \frac{B}{x-b} + \frac{C}{x-c}[/itex] by a suitable choice of constants [itex]A[/itex], [itex]B[/itex], [itex]C[/itex].
 
Thanks guys, I got it with partial fraction decomposition.

I also realized I was heading the wrong way since I was finding the relationship between v and t while the question prompted to find the relationship between v and y. So I did a=dv/dt=dy/dt * dv/dy=v*dv/dy to solve the problem.

It wasn't too tough after that. Thanks for all the help guys, I really appreciate it
 

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