Newtons 3rd law+Horse Cart System+Action/Reactonhelp needed

  • Thread starter Thread starter x0xgreenxeyezx0x
  • Start date Start date
  • Tags Tags
    Cart Newtons
AI Thread Summary
The discussion centers on understanding Newton's third law of motion, particularly in the context of a horse-cart system. When standing still, the forces between a person and the Earth are indeed action-reaction pairs, with gravity and normal force at play. In the horse-cart scenario, the horse can accelerate the cart by exerting force on it, while the horse itself accelerates due to the ground's reaction force. The system as a whole accelerates because of the ground's action on both the horse and the cart. Clarifying these concepts is crucial for mastering the principles of action and reaction in physics.
x0xgreenxeyezx0x
Messages
1
Reaction score
0
Newtons 3rd law+Horse Cart System+Action/Reacton..help needed ASAP!

im a sophmore in the ib program and I'm in conceptual physics

i have a test tommorow on Newtons third law and all the stuff that goes along with it.. so i need an answer on this pronto!

first of all.. if you are standing still.. is the considered an action/reaction force? i thought it was.. because the Earth exerts a force up on you and you exert a force down on the earth..? but for some reason, my friend said it wasn't.. and i don't know..?

then i have a question on the horse-cart system.. idk if you know of this but its an example found in a lot of textbooks.. and it shows a horse attatched to a cart and the horse says 'I cannot accelerate this cart because the forces are equal and opposite of me and the cart and will cancel to zero'.. well i know that's not true.. but why.. and i also need to know..
a)what makes the cart accelerate
b)what makes the horse accelerate
c)what makes the horse-cart system accelerate

i need someone who KNOWS for SURE about this.. please do not give me a bogus answer and make me fail my test tommorow!
 
Physics news on Phys.org
well the standing still question is an action reaction pair and the other big question i think i know but, I am not very good at describing stuff so sorry
 
Strictly speaking, there are two action/reaction couples in the standing still scenario:
1. Gravity: Earth pulls you down, you pull the Earth up. Lots of motion here if it weren't for:
2. Normal force couple: The ground resists your hurtling down to the Earth's C.M, pushing you up, while you push the ground down.

Net result: both you and Earth at rest, with some stress contained in both of you.

Horse+cart:
a) Cart accelerates due to the horse's action upon it.
b) Horse accelerates due to the ground's action upon it.
c) Horse+Cart accelerates due to the ground's action upon them.
 
Last edited:
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Back
Top