Newton's Laws and coefficient of static friction

AI Thread Summary
The discussion focuses on calculating the maximum horizontal force that can be applied to a 5.00-kg block resting on a 12.0-kg block, with a coefficient of static friction of 0.600. It examines whether the force of friction remains the same when the force is applied to either block. The participants agree that the normal force from the smaller block is responsible for the friction in both scenarios. The conclusion is that the normal force influences the frictional force, which is critical for determining slipping conditions. Understanding these dynamics is essential for solving the problem accurately.
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A 5.00-kg block is placed on top of a 12.0-kg block that rests on a frictionless table. The coefficient of static friction between the two blocks is 0.600. What is the maximum horizontal force that can be applied before the 5.00-kg block begins to slip relative to the 12.0-kg block, if the force is applied to (a) the more massive block and (b) the less massive block?

In this problem does the force of friction have the same magnitude in both A and B? My logic is that it is only the normal force of the small mass that cause the friction in both cases. Is this correct?
 
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jehan4141 said:
A 5.00-kg block is placed on top of a 12.0-kg block that rests on a frictionless table. The coefficient of static friction between the two blocks is 0.600. What is the maximum horizontal force that can be applied before the 5.00-kg block begins to slip relative to the 12.0-kg block, if the force is applied to (a) the more massive block and (b) the less massive block?

In this problem does the force of friction have the same magnitude in both A and B? My logic is that it is only the normal force of the small mass that cause the friction in both cases. Is this correct?

Your assertion about normal force seems sound.
 

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