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KiNGGeexD
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I am a little stumped with this question:( I have attached my solution so far which has just been to deduce the acceleration on the flat surface
KiNGGeexD said:View attachment 65423
I am a little stumped with this question:( I have attached my solution so far which has just been to deduce the acceleration on the flat surface
View attachment 65424
You should show us how you get that. What is the initial speed in m/s? Plot speed in m/s vs. time on a graph. What does the area under the graph represent? Work out the formula for that area and express in terms of change in speed and time.KiNGGeexD said:Ahh ok!
I determined the time to stop as 10 seconds and acceleration to be 0.3m/s^2:)
Work it out using m for the car mass. You will see that mass cancels out.So how do I get the kinetic friction coefficient without the mass of the car?
Determine the time it takes to stop. Your calculation of 10 seconds is wrong. How do you determine acceleration from the stopping time and initial velocity?KiNGGeexD said:I got
a= g(sinθ - μcosθ)
But it occurs to me I don't have the acceleration
Acceleration is the rate at which an object's velocity changes over time. It is a vector quantity, meaning it has both magnitude and direction.
Acceleration on a flat surface can be calculated by dividing the change in velocity by the change in time. The formula for acceleration is a = (vf - vi) / t, where vf is the final velocity, vi is the initial velocity, and t is the time interval.
Acceleration is typically measured in meters per second squared (m/s^2) in the metric system. In the imperial system, it can be measured in feet per second squared (ft/s^2) or miles per hour squared (mi/h^2).
The mass of an object does not directly affect its acceleration on a flat surface. However, a greater mass may require more force to achieve the same acceleration as a smaller mass.
Yes, acceleration can be negative on a flat surface. This indicates that the object is decelerating or slowing down. Negative acceleration is also known as deceleration or retardation.