Newton's Second Law of Motion homework problem

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An applied force accelerates mass A at 6.0 m/s² and mass B at 8.0 m/s², leading to equations F = mA * 6.0 and F = mB * 8.0. By expressing the masses in terms of force and acceleration, mA = F/6.0 and mB = F/8.0, these values can be substituted into the equation for both masses together, F = (mA + mB) * a. When substituting, the force cancels out, allowing for the calculation of the resulting acceleration when both masses are accelerated together. The final result demonstrates how to find the combined acceleration using Newton's Second Law.
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An applied force accelerates mass A at a rate of 6.0m/s^2. The same force applied to mass B accelerates the mass at a rate of 8.0m/s^2. If the same force were used to accelerate both masses together, what would be the resulting acceleration be?
 
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set up a set of equations using F=ma for different m and a
 
jalen said:
An applied force accelerates mass A at a rate of 6.0m/s^2. The same force applied to mass B accelerates the mass at a rate of 8.0m/s^2. If the same force were used to accelerate both masses together, what would be the resulting acceleration be?

write the second law for the first case, the second case and the third case

F= (mass of a)*(6.0)
F= (mass of b)*(8.0)
F= (mass of a + mass of b)*(acceleration)


the first two equations give us the mass of a and mass of b in the form:

m=F/a

substitute them into the third equation and solve for acceleration. the force cancels out.
 
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