How High Should a Marble Be Released to Propel a Steel Ball at 150cm/s?

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To determine the height from which a 100g marble should be released to propel a 200g steel ball to 150 cm/s, conservation of energy principles can be applied. The marble's potential energy at height h converts to kinetic energy at the bottom of the incline. The necessary velocity of the marble can be calculated using kinetic energy formulas. Assuming no friction, the equation mgh = 1/2 mv² can be utilized to find the required height. The discussion emphasizes the importance of energy conservation in solving the problem.
darkdryad
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I'd be grateful if anyone could help me for this question

"A 100g marble rolls down a 40 degrees incline. At the bottom, just after it exits onto a horizontal table, it collides with a 200g steel ball at rest. How high above the table should the marble be released to give the steel ball a speed of 150cm/s?"

thx
 
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What have you tried so far?
 
i suppose there is no friction? In that case use conservation of total energy.

Using the formula of kinetic energy you can calculate the velocity of the marble necessary to give the ball it's given velocity.

Then use conservation of energy for the marble : mgh + 0 = 1/2*m*v² + 0

At height h the velocity is 0 and at the endpoint the height is 0...
 

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