No gravity at center of earth= no pressure?

AI Thread Summary
Gravity at the center of the Earth is zero due to the cancellation of gravitational forces from surrounding mass, but this does not mean there is no pressure. The immense weight of the Earth's layers above creates significant pressure at the center, despite the lack of gravitational pull. As one moves away from the center, gravitational force increases, contributing to the pressure felt. The discussion clarifies that while gravity is absent at the center, the surrounding mass still exerts pressure, similar to how an object is crushed under weight despite having no net force acting on it. Understanding this concept is crucial for grasping the relationship between gravity and pressure within celestial bodies.
  • #151
sophiecentaur said:
That is a deep philosophical point. Isn't it all a man-made invention? Fields are only a way of interpreting what we see happening to things. The whole thing can be looked at in terms of Energy just as well. You can never say what things 'really' are. You can only use models and the Force model may have its appeal to you because it sort of feels right - nothing more.

Try some QM using forces alone - that could prove tricky.

I don't think it is philosophical at all. When I'm in a field there is energy in that field for me to interact with. So if I am in the center of Earth is there energy from the gravitational field, not counting my own field. How could my clock tell the difference between being in a place where the field canceled to be zero or where the field was zero because there was no energy around. If there is no energy around I don't see how my clock could tell the difference.
 
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  • #152
cragar said:
I don't think it is philosophical at all. When I'm in a field there is energy in that field for me to interact with. So if I am in the center of Earth is there energy from the gravitational field, not counting my own field. How could my clock tell the difference between being in a place where the field canceled to be zero or where the field was zero because there was no energy around. If there is no energy around I don't see how my clock could tell the difference.

By definition, a field has a value everywhere. That value may be zero in some places, but the point is that at the centre of the Earth, an object does indeed interact with the gravitational field, a field which extends to infinity.
 
  • #153
I was also interested in the kinds of conditions where gravity would be its greatest.

Someone suggested a black hole. And a black hole would have a huge mass occupying a very small volume something like Jupiter but the size of a speck of dust.

So the center of the speck would have zero gravity and zero pressure?
 
  • #154
Malibuguy said:
I was also interested in the kinds of conditions where gravity would be its greatest.

Someone suggested a black hole. And a black hole would have a huge mass occupying a very small volume something like Jupiter but the size of a speck of dust.

So the center of the speck would have zero gravity and zero pressure?

No, the singularity of a black hole has zero volume and infinite density. There is no center of a singularity in those conditions.
 
  • #155
Drakkith said:
How's this sophie? The net force of gravity is zero at the center of the earth. The FORCE of gravity combines to equal out in every direction, just like pushing in on all sides of a box with equal force results in no net force in a direction.

That makes perfect sense because you use the term Force of Gravity, which removes ambiguity. I think you would agree that a statement about an 'electrical' situation that talked about "electricity in a wire" could introduce confusion. You would want to know whether Current, Charge, Voltage or Power was being referred to.
My problem was with the generic word "gravity".
There is nothing special about the addition (integral) of all forces on an object at the centre of a planet. The effect of gravity is always the sum of all the forces. On the surface, you are being pulled in all directions (particularly in the 'downward' hemisphere) by all constituent parts of the planet. The resultant happens to be vertically downwards (towards the centre of mass). For other, non-spherical, shapes, the CM will not always be the point of attraction.
 
  • #156
Malibuguy said:
I was also interested in the kinds of conditions where gravity would be its greatest.

Someone suggested a black hole. And a black hole would have a huge mass occupying a very small volume something like Jupiter but the size of a speck of dust.

So the center of the speck would have zero gravity and zero pressure?

Despite what has been written all through this thread, you are still, somehow, wanting pressure to be linked, inexorably, to gravity. Whilst you can say that pressure is often caused by gravitational attraction, it can, at least in principle, be protected against - where gravitational forces of course cannot. Moreover, you can generate high pressure in conditions involving very low gravitational fields.
 
  • #157
Malibuguy said:
...a huge mass occupying a very small volume something like Jupiter but the size of a speck of dust.
To be accurate: something like 3x the size of the sun at a minimum, but with theoretically zero volume.


Malibuguy said:
So the center of the speck would have zero gravity and zero pressure?

No. The center of the BH is beyond currently understood physics.
 
  • #158
cragar said:
I don't think it is philosophical at all. When I'm in a field there is energy in that field for me to interact with. So if I am in the center of Earth is there energy from the gravitational field, not counting my own field. How could my clock tell the difference between being in a place where the field canceled to be zero or where the field was zero because there was no energy around. If there is no energy around I don't see how my clock could tell the difference.

How do you 'Know' the gravitational field is there? You may be aware of having measured or experienced a force in the place you are standing but it is a complete act of faith that there is actually something one metre to the right. That Vector Field we all believe in is only there when we actually measure it - when there is some object for it to act on. Of course I believe in fields but only because they are a good model to work with. And why should a (vector) gravitational field be any more 'real' than a scalar field like gravitational potential? I think your initial response shows that you may need to think about things more deeply. Nothing is 'obvious'.

Did you ever consider that, whilst You are in the Earth's gravitational field and you Weigh a certain amount, the Earth is also in Your gravitational field. SO, are there two fields? Is it the two fields interacting or is it 'just' a force between two things? Or is it all 'just the way we look at things'?

Now tell me there's no Philosophy involved. :wink:
 
  • #159
sophiecentaur said:
That makes perfect sense because you use the term Force of Gravity, which removes ambiguity. I think you would agree that a statement about an 'electrical' situation that talked about "electricity in a wire" could introduce confusion. You would want to know whether Current, Charge, Voltage or Power was being referred to.
My problem was with the generic word "gravity".
There is nothing special about the addition (integral) of all forces on an object at the centre of a planet. The effect of gravity is always the sum of all the forces. On the surface, you are being pulled in all directions (particularly in the 'downward' hemisphere) by all constituent parts of the planet. The resultant happens to be vertically downwards (towards the centre of mass). For other, non-spherical, shapes, the CM will not always be the point of attraction.

I already explained that in post # 93 and #95. For some reason I suddenly had you and doc questioning what I was explaining. It's so confusing!
 
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  • #160
sophiecentaur said:
How do you 'Know' the gravitational field is there? You may be aware of having measured or experienced a force in the place you are standing but it is a complete act of faith that there is actually something one metre to the right. That Vector Field we all believe in is only there when we actually measure it - when there is some object for it to act on. Of course I believe in fields but only because they are a good model to work with. And why should a (vector) gravitational field be any more 'real' than a scalar field like gravitational potential? I think your initial response shows that you may need to think about things more deeply. Nothing is 'obvious'.

Did you ever consider that, whilst You are in the Earth's gravitational field and you Weigh a certain amount, the Earth is also in Your gravitational field. SO, are there two fields? Is it the two fields interacting or is it 'just' a force between two things? Or is it all 'just the way we look at things'?

Now tell me there's no Philosophy involved. :wink:

ok, maybe I should go think about it some more.
 
  • #161
@ Drakkith , when you said that if your in the center of a hollow cavity in the earth, you still attract everything around you. I guess we could say that if you exert a force on the Earth around you, then it exerts a force on you as well. Or maybe I am over simplifying it.
 
  • #162
cragar said:
@ Drakkith , when you said that if your in the center of a hollow cavity in the earth, you still attract everything around you. I guess we could say that if you exert a force on the Earth around you, then it exerts a force on you as well. Or maybe I am over simplifying it.

It's easy cragar. Every particle exerts gravitational force on every other particle, with increasing strength as they get closer to each other. That's all it is right there. Everything else just builds on that one piece. Pressure is simply how much force you have to exert against those particles to keep them from getting closer together. The complicated part is adding in more particles.

I think the biggest problem in this thread has been incorrect use of terms. You ALWAYS experience the force from an object. If you have an equal amount of force pushing or pulling you in every direction you have no NET force, which means that you won't be pushed or pulled from your current position, but the forces are still pushing or pulling on you.
 
  • #163
To calculate the pressure you have to consider an infinitesimal area element around the center of the Earth and calculate the force acting on it per unit area. To get the value at the center of the earth, we need to take the infinitesimal limit of the above quantity, which need not be zero.
 
  • #164
Avijeet said:
To calculate the pressure you have to consider an infinitesimal area element around the center of the Earth and calculate the force acting on it per unit area. To get the value at the center of the earth, we need to take the infinitesimal limit of the above quantity, which need not be zero.

What?
 
  • #165
Drakkith said:
It's easy cragar. Every particle exerts gravitational force on every other particle, with increasing strength as they get closer to each other. That's all it is right there. Everything else just builds on that one piece. Pressure is simply how much force you have to exert against those particles to keep them from getting closer together. The complicated part is adding in more particles.

I think the biggest problem in this thread has been incorrect use of terms. You ALWAYS experience the force from an object. If you have an equal amount of force pushing or pulling you in every direction you have no NET force, which means that you won't be pushed or pulled from your current position, but the forces are still pushing or pulling on you.

ok I see what you are saying.
 
  • #166
Being in the center of an object's gravitational field means being where it is densest. So you would be closer and more affected by the gravitational fields of its densest components. You would have the all attractive forces of all the parts of the object centered on you.
 
  • #167
Corrected:
treehouse said:
Being in the center of an object's gravitational field usually means being where it is densest.

It is certainly not the case for the hollow spheres we are often referring to here.

treehouse said:
You would have the all attractive forces of all the parts of the object centered on you.
I do not know what this means. It sounds like a sloppy use of terms.
 
  • #168
Well the center of the Earth has been further subclassified as have an "inner inner core"
The outer core is liquid iron and the inner core a solid but very hot iron. The extreme pressure of the inner core is counter acted by the high temperature. When the inner core cools a little it will probably change and perhaps the solid metal will shrink in size and grow more dense.

Neutrons have been observed to ascend to a quantum higher level when exposed to gravitational field. The quantum character of these neutron states may provide some explanation why objects fall at the same rate.

But it would be nice to know what happens to the Neutron when it has come to rest on the earth. Do the close proximity of neutrons to other neutrons generate gravity? Denser materials have more neutrons and generate more gravity? Can gravity byitself change atoms so the the electron cloud can get pushed out and neutron and protons get closer together ?
 
  • #169
But it would be nice to know what happens to the Neutron when it has come to rest on the earth. Do the close proximity of neutrons to other neutrons generate gravity? Denser materials have more neutrons and generate more gravity?

A free neutron doesn't "come to rest" in the earth. The uncharged nature of the neutron means that it does not interact with electrons and only interacts with protons when it gets very very close and is at the right velocity to be captured into the nucleus, if possible. Otherwise they pass through most materials and "bounce" off the nucleus, losing speed each time. Every 15 minutes outside of the nucleus of an atom, a neutron has a 50% chance of decaying into a proton. The only exception is extreme gravity such as in a Neutron star.

Anyways, your view suggests that neutrons exert gravity but not other matter? If so this is entirely false, as a quick look at the Sun will show you. All matter, protons and electrons included, generate a gravitational field. In fact, all mass generates a gravitational field along with "massless" photons since they have momentum.
Can gravity byitself change atoms so the the electron cloud can get pushed out and neutron and protons get closer together ?

I don't know what you mean by this.
 
  • #170
Thanks. No I wasn't implying that a free neutron comes to
Rest on the earth. I was thinking about the object that comes to rest on the Earth now becomes part if the gravitational mass of the earth. What happens to the quantum state of the neutrons?

I wasn't implying that neutrons are the only thing that create gravity. I was just trying to talk about some interesting possibilities due to what is known about neutrons.

As far as electron clouds go , I was trying to get a better idea of what happens to the iron or other matter when it becomes hyperdense. In order to increase density one has to get the neutrons and protons closer together. Neighboring atoms might getnso close that their electron clouds might get distorted or maybe the electron and proton would meet and annihilate.
 
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  • #171
Ah, I see what you are saying now. I have to ask though, where did you hear about some quantum state of neutrons changing in a gravitiational field? I've never heard of that before.
 
  • #172
There was a study done you can google neutrons and gravity field.

But the idea of super dense matter , to me , implies changes to the atomic structure. There is a lot of empty space in an atom with the
Distance of the electrons and maybe even the space
Within a neutron or proton
 
  • #173
Though you would have no effect of gravity, but the outer layer is NOT a RIGID body, it would fall towards the centre where potential is at minimum.

The shell model postulates that the shell is a rigid body, so it would not collapse, but I don't think Earth is completely rigid to resist such an enormous gravity

And for the sun it's obvious that plasma is no rigid body. Plasma particles move extremely fast which is a sort of pressure.
 
  • #174
Malibuguy said:
There was a study done you can google neutrons and gravity field.

But the idea of super dense matter , to me , implies changes to the atomic structure. There is a lot of empty space in an atom with the
Distance of the electrons and maybe even the space
Within a neutron or proton

Yes, I believe that the electron shells aren't at their minimum energy/size, as the atoms have thermal energy and such. Hence one of the reasons cooling a substance typically, but not always, causes contraction.
 
  • #175
Drakkith said:
Yes, I believe that the electron shells aren't at their minimum energy/size, as the atoms have thermal energy and such. Hence one of the reasons cooling a substance typically, but not always, causes contraction.

What? You seem to be suggesting that cooling a substance reduces the size of its atoms/electron shells, as opposed to reducing the space between atoms. I'd want that backed up.
 
  • #176
DaveC426913 said:
What? You seem to be suggesting that cooling a substance reduces the size of its atoms/electron shells, as opposed to reducing the space between atoms. I'd want that backed up.

I'm suggesting both. I thought it was "common knowledge" that electrons around an atom were always moving between different energy levels. If so, they obviously would have to move into larger orbitals than their minimum energy levels are. The actual size of each orbital doesn't change, just that the electrons are moving to higher ones and coming back down. Is that incorrect?
 
  • #177
Higher energy orbitals does not necessarily means further from the nucleus.
It is the energy which is higher (greater) not the height (distance).
Sloppy use of terminology really, but very common.

Remember that for individual atoms the orbitals have different shapes (s,p,d,etc) and the shapes for molecular orbital in solids are different again.

The 'shells' are not concentric spheres.
 
  • #178
Drakkith said:
I'm suggesting both. I thought it was "common knowledge" that electrons around an atom were always moving between different energy levels. If so, they obviously would have to move into larger orbitals than their minimum energy levels are. The actual size of each orbital doesn't change, just that the electrons are moving to higher ones and coming back down. Is that incorrect?

It's not really relevant at normal temperatures. It's true that in gases, electrons can be in higher than base energy levels, but the temperature required for a significant fraction of them to be in any state other than the base one is in the thousands of kelvin (possibly tens of thousands - it's been a while since I've done the math). It's relatively easy to calculate with the Boltzmann Equation though:

http://spiff.rit.edu/classes/phys440/lectures/boltz/boltz.html
 
  • #179
Studiot said:
Higher energy orbitals does not necessarily means further from the nucleus.
It is the energy which is higher (greater) not the height (distance).
Sloppy use of terminology really, but very common.

Remember that for individual atoms the orbitals have different shapes (s,p,d,etc) and the shapes for molecular orbital in solids are different again.

The 'shells' are not concentric spheres.

Of course. I only thought that in general an electron occupying a higher energy slot is further away from the nucleus. But I can see how they wouldn't make a significant difference in the average distance between nuclei.

cjl said:
It's not really relevant at normal temperatures. It's true that in gases, electrons can be in higher than base energy levels, but the temperature required for a significant fraction of them to be in any state other than the base one is in the thousands of kelvin (possibly tens of thousands - it's been a while since I've done the math). It's relatively easy to calculate with the Boltzmann Equation though:

http://spiff.rit.edu/classes/phys440/lectures/boltz/boltz.html

I see. Does that equation apply to non gasses?
 
  • #180
No I do not mean the interatomic distance ( distance between nuclei).

http://winter.group.shef.ac.uk/orbitron/

Please these orbital exist side by side in space, not in shells like onions.

The boltzman distribution curve gives an energy distribution, not a spatial one.
 
  • #181
Studiot said:
No I do not mean the interatomic distance ( distance between nuclei).

http://winter.group.shef.ac.uk/orbitron/

Please these orbital exist side by side in space, not in shells like onions.

The boltzman distribution curve gives an energy distribution, not a spatial one.

Electrons occupy such interesting orbitals! So are you saying that the electrons in the 2p and 6p orbitals are equidistant from the nucleus?
 
  • #182
It varies, but all the dumbell types (p, d) have a component right up to the nucleus where.

An interesting question is how they all co-exist in an atom with a lot of electons!
 
  • #183
Easy. Because they are wavelike and have no choice!
 
  • #184
Because they are wavelike and have no choice!

Yes, true but still interesting.
:smile:
 
  • #185
Studiot said:
Yes, true but still interesting.
:smile:

Then it depends on what exactly the electrons are doing. Do they occupy the entire orbital all at once, or are they found as a pointlike object within them?
 
  • #186
Drakkith said:
Then it depends on what exactly the electrons are doing. Do they occupy the entire orbital all at once, or are they found as a pointlike object within them?

The orbital is nothing but a probability cloud. When you measure the position of the electron, it will be found within that cloud - with no indication as to what it was doing before the moment of measurement and no indication as to what it might do after the moment of measurement. The shape of the cloud simply defines the probability of where it will be found at that moment.

So, the latter.
 
  • #188
This thread went off the rails around post 168, with discussion about neutrons. It should be split into a separate thread.
 
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