Noble Gas Electron Configurations for Ions: Na+, H-, O2-

AI Thread Summary
Na+, H-, and O2- all have electron configurations that match those of noble gases. Na+ and O2- both achieve the electron configuration of Neon, while H- matches that of Helium. The responses confirm the accuracy of this assessment. The discussion emphasizes the importance of understanding electron configurations in relation to noble gases. Overall, the conclusions drawn about these ions are correct.
phys1618
Messages
105
Reaction score
0

Homework Statement



state whether or not these ions have electron configurations of a noble gas: Na+, H-,O2-

Homework Equations





The Attempt at a Solution



I said yes to all three. Because Na+ and O2- has electron configuration of Neon. H- has electron configuration of Helium.
If I'm wrong, please correct me and explain to me about it. Thank you so much for yall time!
 
Physics news on Phys.org
thank you
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
Back
Top