Nodal Circuit Analysis using KCL

[Canaldigger]

Homework Statement

I(a)= 11A, I(b)= 2.5A, I(c)= 3A. Apply KCL at node X to find I(x).

This question seems really simple as it tells me what to do and where to do it, but am I missing something or not remembering to apply some concept?

The Attempt at a Solution

My attempt: I assigned current flowing towards node x as positive and away as negative.
Ʃi=0; I(a)+I(b)-I(c)-I(x) = 0
After plugging in, I(x) = 10.5A
Is that all there is to the question?
I don't think this answer is correct and rather I should redraw the circuit as a three loop one and use Current divider equations.

 

[gneill]

For the given circuit component values the given current values are nonsense.

If you take the current values at face value and ignore the component values, then your answer (Ix = 10.5A) is fine. Otherwise, for the circuit as specified, the given current values are utter nonsense.

Shame on the one(s) who created the problem; they should not be teaching.

 

[Canaldigger]

For the given circuit component values the given current values are nonsense.

If you take the current values at face value and ignore the component values, then your answer (Ix = 10.5A) is fine. Otherwise, for the circuit as specified, the given current values are utter nonsense.

Shame on the one(s) who created the problem; they should not be teaching.

I will email them and see if there was a typo or something. I was wondering why my values didn't match up when using KVL or any other equations that could apply to a circuit. I had an inkling that the figures might be wrong.

Thanks for help! This problem was driving me crazy.

 

[gneill]

I will email them and see if there was a typo or something. I was wondering why my values didn't match up when using KVL or any other equations that could apply to a circuit. I had an inkling that the figures might be wrong.

Thanks for help! This problem was driving me crazy.

No problem. That's why we're here