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Nodal Circuit Analysis using KCL

  1. Jun 2, 2013 #1
    1. The problem statement, all variables and given/known data

    [Broken]
    I(a)= 11A, I(b)= 2.5A, I(c)= 3A. Apply KCL at node X to find I(x).

    This question seems really simple as it tells me what to do and where to do it, but am I missing something or not remembering to apply some concept?


    3. The attempt at a solution
    My attempt: I assigned current flowing towards node x as positive and away as negative.
    Ʃi=0; I(a)+I(b)-I(c)-I(x) = 0
    After plugging in, I(x) = 10.5A
    Is that all there is to the question?
    I don't think this answer is correct and rather I should redraw the circuit as a three loop one and use Current divider equations.
     
    Last edited by a moderator: May 6, 2017
  2. jcsd
  3. Jun 2, 2013 #2

    gneill

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    Staff: Mentor

    For the given circuit component values the given current values are nonsense.

    If you take the current values at face value and ignore the component values, then your answer (Ix = 10.5A) is fine. Otherwise, for the circuit as specified, the given current values are utter nonsense.

    Shame on the one(s) who created the problem; they should not be teaching.
     
  4. Jun 2, 2013 #3
    I will email them and see if there was a typo or something. I was wondering why my values didn't match up when using KVL or any other equations that could apply to a circuit. I had an inkling that the figures might be wrong.

    Thanks for help! This problem was driving me crazy.
     
  5. Jun 2, 2013 #4

    gneill

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    Staff: Mentor

    No problem. That's why we're here :smile:
     
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