Non-Relativistic Scattering: Born Approximation for Particle-Wave Vector k

  • Thread starter Thread starter MathematicalPhysicist
  • Start date Start date
MathematicalPhysicist
Science Advisor
Gold Member
Messages
4,662
Reaction score
372

Homework Statement


Consider a non-relativistic scattering of a particle of mass m and charge e from a fixed distibution of charge \rho(r). Assume that the charge distribution is neutral, \int d^3r \rho(r) =0, it's spherically symmetric, and the second moment is defined as:
A=\int d^3r r^2\rho(r).
Use the Born approximation to derive the differential cross section for the scattering of a particle of wave vector k.


Homework Equations


Let q=2ksin(\theta/2) and the amplitude of the differential cross section to be:
f(\theta)=(-2m/(q\hbar^2))\int_{0}^{\infty} rV(r)sin(qr)dr
(for a spherically symmetric potential).
N.B
theta is the scattering angle.

The Attempt at a Solution


To do the calculation all I need to know is what is the potential,
now the constant A has magnitude of charge times displacement squared, which means eA/r^3 will give units of potetnial energy, but when I insert this I get that the integral doesn't converge, am I wrong here?
If it were the first moment then the integral will converge (the known intgral of sin(x)/x on the etire real line).
Any suggestions here?

Thanks in advance.
 
Physics news on Phys.org
Anyone?
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
Back
Top