- #1

mybrohshi5

- 365

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## Homework Statement

I am studying for my physics exam on tuesday and i came across this question and i am not sure why this equation was used.

A bicycle and bicyclist of combined mass 62 kg go over a circular hump of radius 6.0 m at a speed of 5.0 m/s.

**What is the normal force on the bicycle at the top of the hump?**

## The Attempt at a Solution

The equation used and answer is..

n - mg = - (mv

^{2})/r

n = - [(62*(5

^{2}))/6] + (62*9.8)

n = 349 N

Can anyone explain why or how to come up with this equation used. I am confused on how and where this comes from. I would have never of thought to do this and would have probably gotten it wrong if it was on the test so any clarification to help me understand would be greatly appreciated.

Thank you :)