Not monotonic with increase/decrease intervals

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Hello,
Would it be correct to say that the function y=|(x^3)-1| is not monotonic, yet increases for every x>0 and decreases for every x<0?
I hope one of you could comment. Thanks!
 
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I'm not sure why you use the word "yet". Any function that "increases for every x>0 and decreases for every x<0" is NOT monotonic, by definition of "monotonic". It is true that this function, because it "increases for every x>0 and decreases for every x<0" is monotonic on x> 0 and on x< 0. But not "monotonic" for all x.
 
Thank you, HallsofIvy, that was certainly helpful :-).
 
peripatein said:
Would it be correct to say that the function y=|(x^3)-1| is not monotonic

Yes, but x=0 isn't the point at which decreasing turns into rising.

Try sketching the graph of f(x)=x³, then of g(x)=x³-1, and then of h(x)=|x³-1|. A rough sketch will do, as long as you make sure you don't add "bumps" which would change the monotonicity.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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