Not sure how to do this angular momentum, torque?

AI Thread Summary
To calculate the torque and angular momentum for the given particles, it's essential to specify the reference point, typically the origin (0,0,0). Torque can be determined using the cross-product of the position vector r and the force vector F, while angular momentum is calculated using the cross-product of the position vector r and the momentum (m*v). The discussion emphasizes the need for clarity in defining the point about which these quantities are measured. Without this specification, the calculations cannot be accurately performed. Understanding these concepts is crucial for solving problems related to angular momentum and torque in physics.
Raylyn
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1. A particle at r = 2x +y + 3z (in m) is acted upon by a force F= 5x - 4y-6z (in N). What is the torque on this object (in Nm)?

2. A 3 kg particle at r = 1x + 2y - 3z (in m) has a velocity v +4x +6y -5z (in m/s). What is the angular momentum of this object (in kg m^2/s)?
 
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Welcome to PF!

Raylyn said:
1. A particle at r = 2x +y + 3z (in m) is acted upon by a force F= 5x - 4y-6z (in N). What is the torque on this object (in Nm)?

2. A 3 kg particle at r = 1x + 2y - 3z (in m) has a velocity v +4x +6y -5z (in m/s). What is the angular momentum of this object (in kg m^2/s)?

Hi Raylyn! Welcome to PF! :smile:

Your questions don't make sense … a torque or an angular momentum has to be measured about a particular point, and your questions don't mention one.

If it means what is the torque or angular momentum about the origin (0,0,0), then you must use the cross-product r x F or r x mV. :smile:
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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