Nowhere Continuous Function Dirichlet Proof

cmajor47
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Homework Statement


Prove that the Dirichlet function is continuous nowhere.


Homework Equations


Dirichlet function = 1 when x is rational, and 0 when x is irrational.


The Attempt at a Solution


I was looking at this proof on http://math.feld.cvut.cz/mt/txtd/1/txe4da1c.htm
At the very end when the creator shows that inf f(x) \neq sup f(x)
how does this tell you that the function is never continuous?
Do the greatest lower bound and least upper bound of a function have to be equal at some point for a function to be continuous?
 
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cmajor47 said:
At the very end when the creator shows that inf f(x) \neq sup f(x)
That's not what he showed.

He showed the infimum (over all P) of U(f,P) was not the supremum (over all P) of L(f,P).

And he wasn't proving anything about continuity anyways; that article is about Riemann integrability.
 
Oh, wow, don't know how I missed that. Thanks!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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