How Do You Calculate Pressure from Number Density and RMS Speed in Argon Gas?

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To calculate the pressure of argon gas using number density and RMS speed, the relevant equations are P = (1/3)(N/V)(m)(v^2 rms) and V rms = sqrt((3)(k)(T)/m). The number density is given as 2.00 x 10^25, and the RMS speed is 455 m/s, but the mass of argon atoms is needed for the pressure calculation. Participants in the discussion suggest determining the mass of argon using Avogadro's number and the periodic table, while also clarifying the concept of number density. The conversation emphasizes the importance of understanding these fundamental concepts to solve the problem effectively.
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Homework Statement


The number density in a container of argon gas is 2.00 X 10^25. The atoms are moving with an rms speed of 455 m/s. What is the pressure inside the container?


Homework Equations


V rms = sqrt( (3)(k)(T) / m)

P = F/A = (1/3)(N/V)(m)(v^2 rms)


The Attempt at a Solution



I have tried manipulating all the equations to somehow find the pressure, but have been unsuccessful. I seem to have all the variables except the mass. So i assume i need to get the mass somehow, any ideas?

Thanks.
 
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What is one mole of gas? What is its volume? What is Avogadro's law?
Answers to these questions will lead to the mass of the argon.
 
Is the moles the number density divided by Avogadro's number? And how do i get the volume? I can't use the ideal gas law since i don't have temperature.
 
You have temperature - look at your equations. Still, looks to me like you should consult periodic table.
 
What excatly is "number density" just a fancy way of saying volume seeing as the units are m^3?
 
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