Number Theory Euclidean Algorithm

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Homework Help Overview

The problem involves number theory, specifically the properties of divisibility and the Euclidean algorithm. The original poster is tasked with demonstrating that if two integers \( u \) and \( v \) are coprime and both divide another integer \( n \), then their product \( uv \) also divides \( n \). The poster is also to show that this statement does not hold if \( u \) and \( v \) are not coprime.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the greatest common divisor (gcd) and linear combinations of \( u \) and \( v \). There is an exploration of how the gcd relates to the divisibility of \( n \) by \( u \) and \( v \). Some participants express uncertainty about how to formally structure their reasoning.

Discussion Status

The discussion is ongoing, with participants questioning the implications of the gcd and how it relates to the problem at hand. Some guidance has been provided regarding the use of linear combinations and the definitions of divisibility, but no consensus or resolution has been reached yet.

Contextual Notes

Participants are grappling with the formal aspects of their reasoning and the implications of the gcd in the context of the problem. There is a recognition that the original poster may need to clarify their understanding of these concepts to proceed effectively.

MathSquareRoo
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Homework Statement



Suppose that u, v ∈ Z and (u,v) = 1. If u | n and v | n, show that uv | n. Show that this is false if (u,v) ≠ 1.

Homework Equations



a | b if b=ac

3. The Attempt at a Solution

I understand this putting in numbers for u,v, and n but I don't know how to formally write it.
 
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Do you know a relation between the gcd and linear combinations of u and v?
 
Linear combination of u and v are equal to the gcd correct? And the gcd divides u and v I believe. I need help organizing all these ideas.
 
MathSquareRoo said:
Linear combination of u and v are equal to the gcd correct?
Not necessarily true for an arbitrary linear combination, but there exists at least one linear combination equal to the gcd.

And the gcd divides u and v I believe.
Certainly, gcd means greatest common divisor, so it's certainly a divisor.

OK, if we let d = the gcd, then you know there is a linear combination such that d = au + bv. Now you know that u divides n and v divides n, so how can you use that fact here?
 
So then au divides n and vb divides n?
 
MathSquareRoo said:
So then au divides n and vb divides n?

No, that isn't necessarily true. However, if u divides n, then n = ur for some integer r. And v divides n, so n = vs for some integer s. Now try using these facts.
 

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