Number Theory Euclidean Algorithm

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SUMMARY

The discussion focuses on the Euclidean Algorithm and its application in number theory, specifically addressing the relationship between two integers u and v when their greatest common divisor (gcd) is 1. It establishes that if u divides n and v divides n, then uv also divides n, provided that (u,v) = 1. The conversation highlights the importance of linear combinations in proving this relationship and clarifies that the gcd is indeed a divisor of both u and v. Additionally, it notes that the statement does not hold if (u,v) ≠ 1.

PREREQUISITES
  • Understanding of the Euclidean Algorithm
  • Knowledge of greatest common divisor (gcd)
  • Familiarity with linear combinations in number theory
  • Basic concepts of divisibility in integers
NEXT STEPS
  • Study the properties of the Euclidean Algorithm in depth
  • Explore linear combinations and their applications in proving number theory theorems
  • Investigate the implications of gcd in divisibility problems
  • Learn about the implications of coprime integers in number theory
USEFUL FOR

This discussion is beneficial for mathematics students, educators, and anyone interested in number theory, particularly those studying divisibility and the properties of integers.

MathSquareRoo
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Homework Statement



Suppose that u, v ∈ Z and (u,v) = 1. If u | n and v | n, show that uv | n. Show that this is false if (u,v) ≠ 1.

Homework Equations



a | b if b=ac

3. The Attempt at a Solution

I understand this putting in numbers for u,v, and n but I don't know how to formally write it.
 
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Do you know a relation between the gcd and linear combinations of u and v?
 
Linear combination of u and v are equal to the gcd correct? And the gcd divides u and v I believe. I need help organizing all these ideas.
 
MathSquareRoo said:
Linear combination of u and v are equal to the gcd correct?
Not necessarily true for an arbitrary linear combination, but there exists at least one linear combination equal to the gcd.

And the gcd divides u and v I believe.
Certainly, gcd means greatest common divisor, so it's certainly a divisor.

OK, if we let d = the gcd, then you know there is a linear combination such that d = au + bv. Now you know that u divides n and v divides n, so how can you use that fact here?
 
So then au divides n and vb divides n?
 
MathSquareRoo said:
So then au divides n and vb divides n?

No, that isn't necessarily true. However, if u divides n, then n = ur for some integer r. And v divides n, so n = vs for some integer s. Now try using these facts.
 

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