Number Theory Euclidean Algorithm

MathSquareRoo
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Homework Statement



Suppose that u, v ∈ Z and (u,v) = 1. If u | n and v | n, show that uv | n. Show that this is false if (u,v) ≠ 1.

Homework Equations



a | b if b=ac

3. The Attempt at a Solution

I understand this putting in numbers for u,v, and n but I don't know how to formally write it.
 
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Do you know a relation between the gcd and linear combinations of u and v?
 
Linear combination of u and v are equal to the gcd correct? And the gcd divides u and v I believe. I need help organizing all these ideas.
 
MathSquareRoo said:
Linear combination of u and v are equal to the gcd correct?
Not necessarily true for an arbitrary linear combination, but there exists at least one linear combination equal to the gcd.

And the gcd divides u and v I believe.
Certainly, gcd means greatest common divisor, so it's certainly a divisor.

OK, if we let d = the gcd, then you know there is a linear combination such that d = au + bv. Now you know that u divides n and v divides n, so how can you use that fact here?
 
So then au divides n and vb divides n?
 
MathSquareRoo said:
So then au divides n and vb divides n?

No, that isn't necessarily true. However, if u divides n, then n = ur for some integer r. And v divides n, so n = vs for some integer s. Now try using these facts.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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