ODE problem: 3x^2 y dx + (x^3 + 2y)dy = 0

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I have two ODE with which I cannot to slove;

3x2ydx+(x3+2y)dy=0

I tried to change of variable y=v*x, but I still cannot find a way to solve it.

the second is:

(exsin(y)-2ysin(x))dx+(excos(y)+2cos(x))dx=0

here I have no idea


thank you
B
 
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They are exact diff equ. Have you not seen how to solve such ode's?
 
Surely you know other techniques for solving ODE? This problem is tailor-made for one of them.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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