Oentane is a liquid with a vapor pressure of 512 Torr at 25C

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To determine the liquid phase composition of a mixture of pentane and hexane that results in equal amounts of each in the gas phase, Raoult's Law is applied. The formula used is P = P_pure_hexane * C_hexane + P_pure_pentane * C_pentane, where P represents the total vapor pressure, P_pure is the vapor pressure of the pure components, and C is the molar composition of each component in the liquid phase. Given that the vapor pressure of pentane is 512 Torr and that of hexane is 151 Torr at 25°C, the goal is to find the molar fractions of pentane and hexane in the liquid phase that would yield equal partial pressures in the gas phase. This involves setting the partial pressures equal to each other and solving for the compositions.
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Oentane is a liquid with a vapor pressure of 512 Torr at 25C; at the same temperature, the vapor pressure of hexane is only 151 Torr. what composition must the liquid phase have if the gas hase composition is to have equal amounts of pentane and hexane?

Do I use p = i M R T to solve for the M, molar masses? How do I need to get started
 
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No, you'll need to use the Rault's law

P=P_{pure~hexane}C_{hexane}+P_{pure~oentane}C_{oentane}

where C=molar composition of respective compound
 
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