1. The problem statement, all variables and given/known data a) For the mechanism shown in figure 1 determine for the angle (45°): i) the velocity (VBO) of the piston relative to the fixed point (O). ii) the angular velocity of AB about point A. iii) the acceleration of point B relative to A. *Note: Link AB is horizontal when angle = 45°. b) Determine the value of the angle (measured from vertical) when: i) the velocity of point b = 0. ii) the angular velocity of link AB a maximum. c) what is the maximum angular velocity of link AB? 2. Relevant equations v=lw (a)r = v^2/l 3. The attempt at a solution l of AO = 50mm = 0.05m l of AB = 200mm = 0.2m w of AO = 300 x 2pi/60 = 31.42 rads^-1 ai) V of AO = l of AO x w of AO. V of A0 = 0.05 x 31.42 V of AO = 1.57ms^-1 *Use this value to draw a velocity diagram (attached). To confirm using trig, Sin(45°) = V of BO/1.57 V of BO = 1.57 x Sin(45°) V of BO = 1.11ms^-1 aii) v=lw therefore w=v/l w of AB = v of AB/l of AB w of AB = 1.11/0.2 w of AB = 5.55 rads^-1 aiii) (a of BA)r = v of BA^2/l of BA (a of BA)r = 1.11^2/0.2 (a of BA)r = 6.16ms^-2 *Tangential velocity is calculated in the acceleration diagram (attached). Radial acceleration of AO calculated below to use in the diagram. (a of AO)r = v of AO^2/l of AO (a of AO)r = 1.57^2/0.05 (a of AO)r = 49.3ms^-2 So, as per the diagram, (a of BA)t = 34.5ms^-2. This is the part where I am starting to struggle, I have had conformation back from my tutor that the first 3 parts to the question look good but I am struggling with parts b & c. If someone could help push me in the right direction then it would be very much appreciated. I am after guidance, not answers, I want to learn.