Physics Problem: Flight Attendant and 70N Bag

[XxClueLess5xX]

ok I am in physics obviously...and I am having an extrmely hard time. can anyone help me with this problem?

- a flight attendant ulls her 70 N flight bag a distance of 253 m along a level airport floor at a constant speed. the force she exerts is 40.0N at an angle of 52 degrees above the horizontal. find the following t work she does on the flight bag.

 

[James R]

What have you done so far?

 

[quicknote]

Sure, I can help you with this problem! First, let's break down the information we have been given. We know that the flight attendant is exerting a force of 40.0N at an angle of 52 degrees above the horizontal. This means that the horizontal component of the force is 40.0N*cos(52) = 24.4N and the vertical component is 40.0N*sin(52) = 30.7N. Next, we know that the bag has a weight of 70N, which means that the force of gravity acting on it is 70N downwards.

Now, since the bag is being pulled at a constant speed, we know that the net force acting on it is 0N (since there is no acceleration). This means that the horizontal force from the flight attendant must be equal to the horizontal component of the weight of the bag. So, we can set up an equation: 24.4N = 70N*cos(theta), where theta is the angle between the bag and the horizontal. Solving for theta, we get theta = arccos(24.4/70) = 72.8 degrees.

Now, we can use this angle to find the work done by the flight attendant on the bag. The work done is equal to the force applied multiplied by the distance traveled in the direction of the force. In this case, the distance traveled is 253m and the force applied is the horizontal component of 40.0N, which is 24.4N. So, the work done is 24.4N * 253m = 6173.2 Joules.

I hope this helps you understand the problem better! Remember to always break down the information given and use equations to solve for the unknowns. Good luck with your physics studies!