One-dimensional undamped harmonic oscillation

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A particle of mass m experiences one-dimensional undamped harmonic oscillation influenced by a restoring force Fr = -kx and a constant external force Fext = Fo. The governing differential equation for the motion is d^2x/dt^2 + kx/m = Fo/m, with the general solution for position given by x(t) = Acos(Wot + phi) + Fo/k. As time approaches infinity, the undamped motion results in perpetual oscillation between positive and negative amplitudes A, while in the case of damped oscillation, the motion would eventually cease as the system loses energy. The introduction of a damping constant alters the solution, leading to a gradual decrease in amplitude over time until the particle comes to rest. Understanding these dynamics is crucial for analyzing real-world oscillatory systems.
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A particle of mass m undergoes one-dimensional undamped harmonic oscillation due to a restoring force Fr = -kx. In addition the particle is subject to a constant external force Fext = Fo.
a) What is the differential equation that governs the motion of the particle?
b) what is the general solution for the position of the particle as a fxn of t?
c) What is the motion of the particle in the limit t - > infinity
d) If the oscillations are damped, what would be the motion of the particle in the limit t-> infinit?

a) d^2x/d^t^2 + kx/m = Fo/m
b) After applying the method of undetermined coefficients
x(t) = Acos(Wot + phi) + Fo/k

c) V = -Asin(Wot+ phi)(Wo)
t-> infiity , v - inifity?

d) If the former was undamped, how does introducing the damping constant change my solution?

Thanks
 
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In (c), if the motion is undamped (also from the math) you see that there is no limit as t approaches infinity. The motion will remain forever oscillating between positive and negative A. If the motion is damped however, like any real spring you have, what is the motion of the spring after you leave it alone for a long time?
 
Thanks a great deal for clarify the concepts.
 
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