One object exerting force on another

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Two steel blocks, X (3.0 kg) and Y (12 kg), are connected by a taut string on a frictionless surface, with a 45 N force applied to block X. The force causes both blocks to accelerate together, and the tension in the string is crucial for understanding the interaction between them. According to Newton's third law, the force block Y exerts on block X is equal and opposite to the force exerted by block X on block Y. To find the force exerted by block Y on block X, one must consider the total mass being accelerated and the applied force. This scenario illustrates the principles of tension and action-reaction forces in a connected system.
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Two steel blocks are at rest on a frictionless horizontal surface. Block X has a mas of 3.0 kg ans is attacthed by means of a light taut string to block Y that has a mass of 12 kg. A force of 45 N (E) is applied to block x. Calculate the force block Y exerts on block x.

I don't have any idea of how to go about do this question. I think it's related to Newton's 3rd law about action-reaction forces but I don't know any else. Could someone please guide me in the right direction? Thanks
 
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There is a taut string - in tension.

The force is applied to one block (X), but because of the string, it affects both blocks of the total mass, and X is pulling on block Y by virtue of the string.

This might help - http://hyperphysics.phy-astr.gsu.edu/hbase/fcm.html#c1
 
Astronuc said:
There is a taut string - in tension.

The force is applied to one block (X), but because of the string, it affects both blocks of the total mass, and X is pulling on block Y by virtue of the string.

This might help - http://hyperphysics.phy-astr.gsu.edu/hbase/fcm.html#c1

Thanks :D
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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