Engineering Op Amp : Design the circuit such that

AI Thread Summary
The discussion revolves around designing an op-amp circuit to achieve the output Vo = Va + 2Vb + 3Vc, assuming an ideal op-amp. Initial attempts included setting up a current equation, but the user struggled with the correct approach and values for resistors Ra and Rc. After some trial and error, the user calculated Ra as 30k and Rc as 10k, and determined the output voltage Vo to be 5.5V based on specific input values. However, there was confusion regarding the feasibility of achieving this output given the op-amp's supply limits. The conversation highlights the importance of correctly applying circuit laws and understanding the limitations of the op-amp configuration.
ElijahRockers
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Homework Statement



JrxFC.jpg

Assume the op amp is ideal.
Design the circuit such that Vo = Va + 2Vb + 3Vc

The Attempt at a Solution



Not sure how to go about this one.

I started with

\frac{V_a}{R_a}+\frac{V_b}{15k}+\frac{V_c}{R_c} = 0 since the op amp is ideal, the sum of the currents going into the non-inverting input must be 0.

From here I haven't got any ideas how to proceed. But what is the voltage at the inputs? I'm assuming it's zero because Vn/20k = 0 : Vn = 0

EDIT: Alright I found Ra to be 30k, Rc to be 10k. Now I have to find the currents ia, ib, and ic, when Va=.5, Vb=.7, and Vc=1.2. Shouldn't that just be Va/Ra =ia? I know one of them must be negative since the total current flowing in must be 0, but how do I know which one?

I found Vo =5.5 at those values for Ra,Rb,Va,Vb,Vc.

Ok... I figured it out. I guess sometimes it just helps to type it out on a forum haha. For anyone wondering, Vo=6Vn (by KCL at the negative terminal). Since Vo = 5.5, then Vn = .9166...
 
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ElijahRockers said:

Homework Statement



JrxFC.jpg

Assume the op amp is ideal.
Design the circuit such that Vo = Va + 2Vb + 3Vc

The Attempt at a Solution



Not sure how to go about this one.

I started with

\frac{V_a}{R_a}+\frac{V_b}{15k}+\frac{V_c}{R_c} = 0 since the op amp is ideal, the sum of the currents going into the non-inverting input must be 0.

This equation is incorrect. Write down the correct KVL equations.
 
ElijahRockers said:
Ok... I figured it out. I guess sometimes it just helps to type it out on a forum haha. For anyone wondering, Vo=6Vn (by KCL at the negative terminal). Since Vo = 5.5, then Vn = .9166...
You really can't get "Vo = 5.5" when the op-amp has supply voltages of ±5 volts. ☹[/size][/color]
 
How can you get numerical answers of any kind when your inputs are symbols?
Are you pulling somebody's leg? :rolleyes:
 
I founded an ebook that very helpful for you: Op amp for every one

www.ti.com/lit/an/slod006b/slod006b.pdf
 
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rude man said:
How can you get numerical answers of any kind when your inputs are symbols?
Are you pulling somebody's leg? :rolleyes:
See post #1
 
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