Op-Amp Slew Rate/Gain-Bandwidth Product

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A high gain-bandwidth product in op-amps can indicate a high slew rate, but this relationship is not always guaranteed as it depends on the maximum output voltage required. For a phase-sensitive detector operating at a reference frequency of 100kHz, the maximum rms voltage for input signals must be calculated considering the specified slew rate of 1V/μs. The maximum slew rate limits the rate of change of the output voltage, which directly affects the input signal amplitude. The discussion highlights the importance of understanding both gain-bandwidth product and slew rate in op-amp applications. Clarifying these concepts is crucial for accurate circuit design and performance analysis.
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The op-amp selected for the unity gain inverter, has a gain-bandwidth product, and maximum slew rate at its output of 1V/μs[/b]
(i) Justify the statement that a high gain-bandwidth product necessarily leads to a high slew rate
(ii) The phase sensitive detector is expected to operate with a reference frequency set at 100kHz. Based on the slew rate given, determine a maximum rms voltage for input signals and explain your reasoning
My problem
Don't really know where can I get the gain-bandwidth product. I feel there's no need to present my attempt at a solution, because it's not the type of question that will require derivation or anything.
Thanks for your help (in advance)
 
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An op amp outputs a voltage V0sin(ωt). What's the maximum slew rate?

(I hate to muddy the water, but actually the statement is not necessarily correct. Hint: it depends on the max output voltage required).
 
Sorry, stupid question. Just needed to differentiation once.
 

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