Optics and waves, mirage. University physics

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SUMMARY

The discussion focuses on deriving the trajectory of a ray of light in an inhomogeneous medium characterized by the index of refraction n(y) = n0(1 + αy). Utilizing calculus of variations and Fermat’s principle, participants derive the trajectory equation y(x) = −1/α + A/n0α*cosh[(n0α/A)(x − x0)]. Key challenges include determining constants A and x0 for rays grazing the ground at specific points. Participants share their approaches, including variable separation and substitutions, to solve the problem effectively.

PREREQUISITES
  • Understanding of calculus of variations
  • Familiarity with Fermat’s principle in optics
  • Knowledge of hyperbolic functions, specifically cosh
  • Basic concepts of ray optics and index of refraction
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  • Learn about the derivation and applications of Fermat’s principle
  • Explore hyperbolic functions and their properties in mathematical physics
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Physics students, optical engineers, and researchers in wave optics seeking to deepen their understanding of light trajectories in varying media.

YogiBear
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Mirage: we consider the x-y plane describing vertical y and horizontal x directions, with an inhomogeneous index of refraction n(y). In this case, using calculus of variations, Fermat’s principle for the trajectory of a ray of light may be re-written as n(y)/√1+(dy/dx)^2 = A. Where A is a real constant, to be determined by boundary conditions. We consider the index of refraction to be n(y) = n0(1 + αy) where n0 and α are real parameters.

Show that the trajectory y(x) of a ray of light is given by
y = − 1/α + A/n0α*cosh [ (n0α/A) * (x − x0) ]

Limits for integration are not given.

What i have done so far: Well i separated variables and then used f(x) = cosh^-1(x) f'(x) = 1/(x^2 -a^2)^1/2 to get pretty close to the solution. However i don't see where n0α/A comes from within the cosh bracket. Also I used x and x0, y and 0, as limits for integration. Huge thanks in advance
 
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Hi Yogibear, I got

y(x) = [exp(-abk - abx)+exp(abk +abx) - 2 b]/2ab

where and b are functions of one or more α, A and/or n0, and k is the constant of integration. I have to adhere to the rules of this forum and not give the explicit functions. If you want more help you'll have to show us more math detail. E.g. what is f(x) and how did you get it?

Note that you can substitute k' = ek. Looks like you might get a cosh term out of that ...
 
Last edited:
rude man said:
Hi Yogibear, I got

y(x) = [exp(-abk - abx)+exp(abk +abx) - 2 b]/2ab

where and b are functions of one or more α, A and/or n0, and k is the constant of integration. I have to adhere to the rules of this forum and not give the explicit functions. If you want more help you'll have to show us more math detail. E.g. what is f(x) and how did you get it?

Note that you can substitute k' = ek. Looks like you might get a cosh term out of that ...

Thanks, I was actually able to solve that part using t = n(y)/A substitution.
However now i have to do the following: "Determine the trajectory y(x) of a ray of light that just grazes the ground at x = xg as shown in the figure (i.e. determine expressions for A and x0 for this ray). Figure, in this case is just a generic x/y plane with y=x^2 graph on it touching x-axis at xg. I have no idea where to start. :/
 

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