Optics question: What two positions of a lens gives a sharp image?

AI Thread Summary
To achieve a sharp image with a +4.5 D thin lens placed between a lamp and a screen 1 meter apart, the lens must be positioned at two specific distances derived from the lens formula. The correct application of the lens formula, 1/l' + 1/l = F, allows for the calculation of the two positions of the lens. By substituting the total distance into the equation, two lens positions can be determined. The magnification at these positions is calculated as either -2 or -1/2. Understanding the lens formula is crucial for solving optics problems effectively.
LeeLoo
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1. A lamp and a screen are 1m apart and a +4.5 D thin lens is mounted between them. Where must the lens be placed in order to produce a sharp image on the screen, and what will be the magnification?



2. Gauss Law: L' = L + F



3. I attempted this question by using the Gauss Law but I just don't know how to find the two possible positions of the lens to give a sharp image. I thought that a sharp image might be formed at F or F' but it doesn't work. Can someone please show me how to do this problem and explain it :)
 
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LeeLoo said:
I thought that a sharp image might be formed at F or F' but it doesn't work.
Why doesn't it work? What do you know about "F" ?
 
Welcome to PF!

LeeLoo said:
Gauss Law: L' = L + F

Hi LeeLoo! Welcome to PF! :smile:

I don't think that's the right law …

shouldn't it have 1/… ? :wink:
 
Oh, yeah, the law is actually n/l + F = n'/l' but i thought people could abbreviate it like that. anyway, yay, i know how to do the question now!

1/l' + 1/l = F
l' +l =1m
l' = 1 - l

so sub that in and get two answers for 'l' which are the lens positions :D

and magnification= l'/l so you get m = -2 or -1/2

COOL!
 
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