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- Thread starter tandoorichicken
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Therefore u have length say = 2sqrt(12-b) &

breadth = b.

Hence Area, [tex]A = b\sqrt{12-b}[/tex].

u will get b=8 and Length=8& breadth 8.

Alternate

Rectangle with max area is a square

u get [tex] b=2\sqrt{12-b}[/tex]

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