# Optimization problem

1. Jan 8, 2004

### tandoorichicken

Find the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve y = 12-x^2

2. Jan 9, 2004

### himanshu121

Since one side is on x-axis then other side will be || x-axis(rectangle) let say y=a then u will x=+sqrt(12-b).

Therefore u have length say = 2sqrt(12-b) &
Hence Area, $$A = b\sqrt{12-b}$$.
u get $$b=2\sqrt{12-b}$$