Optimizing Boom Length for Oil Spill Containment: A Calculus Approach

sweet877
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To contain oil spills, rectangular booms that have a cross-link to provide stability are used. The cross-link joins the long sides and is parallel to the short sides. What is the minimum total length of boom required to enclose an oil spill covering 100 000 m^2 of water if it can only be constructed from 10-m sections?

I figured out how to do this if 10-m sections are not required, but cannot figure out what to do if the booms have restrictions. Please advise. Thanks!
 
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What length and width do you get if 10-m sections are not required? What are the closest multiples of 10 larger than that?
 
250 m and 400 m. But I just got that from common sense. Is there a "calculus way" to do it?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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