How does the orbital diameter of 2003 UB313 compare to its orbital period?

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The discussion centers on the orbital characteristics of 2003 UB313, noting its elongated orbit that reaches up to 97 times the distance from the Sun compared to Earth. It takes approximately 558 years to complete an orbit, which is about 2.25 times longer than Pluto's 248-year period. The relationship between orbital diameter and period is clarified using Kepler's law, which states that the square of the orbital period is proportional to the cube of the semi-major axis. The semi-major axis of UB313 is 67.7 AU, making it 1.7 times farther from the Sun than Pluto. This analysis confirms that there is a direct correlation between orbital diameter and orbital period, emphasizing the importance of using the semi-major axis for accurate calculations.
DaveC426913
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Is this true?

(excerpted from http://www.astro.uni-bonn.de/~bertoldi/ub313/" about 2003 UB313)

"...Its very elongated orbit takes it up to 97 times farther from the Sun than is the Earth - almost twice as far as the most distant point of Pluto's orbit – so that it takes twice as long as Pluto to go around the Sun..."

Is there a direct correlation between orbital diameter and orbital period? I would have thought it would be logarthmic.
 
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DaveC426913 said:
Is this true?

(excerpted from http://www.astro.uni-bonn.de/~bertoldi/ub313/" about 2003 UB313)

"...Its very elongated orbit takes it up to 97 times farther from the Sun than is the Earth - almost twice as far as the most distant point of Pluto's orbit – so that it takes twice as long as Pluto to go around the Sun..."

Is there a direct correlation between orbital diameter and orbital period? .

Yes there is...
but they've made very rough verbal approximations.
Actually to make orbital period determinations you must use the semi-major axis of the orbit.
In this case the semi- major axis of UB313 is 67.7 AU compared to Pluto's 39.5 AU. So it is really only 1.7 times as distant as Pluto.

The orbital period vs. orbital radius (s-m axis) scales as T^2/R^3, (Kepler's law).

So the period T = sq.rt.(1.7)^3 = 2.25, meaning its orbital period is 2.25 times that of Pluto.
Since Pluto's orbital period is 248 yrs, then the orbital period of UB313 is about 558 yrs. -- Approximately since all my figures are truncated.

Creator:biggrin:
 
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