Orthogonal Functions | Homework Statement

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Homework Statement




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The Attempt at a Solution



All functions orthogonal to 1 result in the fact that: \int_a^b f(t)\ \mbox{d}t =0

Now the extra condition is that f must be continous. (because of the intersection).

But where does the fact that f(a)=f(b)=0 comes from? And why look at the deratives?
 
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Remember way back in first year calc, when you learned that to do that integral you find an antiderivative F(x) and evaluate F(b)-F(a). This is that same problem in disguise.
 
Well I thought of this: \int_a^b \int_a^t f(s)\ \mbox{d}s \mbox{d}t =0
 
dirk_mec1 said:
Well I thought of this: \int_a^b \int_a^t f(s)\ \mbox{d}s \mbox{d}t =0

Fine. What are you going to do with it? Why don't you just define <br /> F(x)=\int_a^x f(s)\ \mbox{d}s<br />
What are some of the properties of F(x)?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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