Does the Belousov-Zhabotinsky Reaction Lead to a Steady State or Oscillations?

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The Belousov-Zhabotinsky reaction does not oscillate indefinitely; it eventually reaches a stationary state when reactants are depleted. The oscillations are a result of complex mechanisms in what is fundamentally a simple reaction. From a mathematical perspective, the system's attractor set is a fixed point corresponding to equilibrium rather than a limit cycle. A limit cycle would only emerge if an infinite supply of reactants were considered. Overall, the reaction transitions from oscillation to a stable state as reactants are consumed.
Llewlyn
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I'm interested in oscillating chemical reaction, as Belousov-Zhabotinsky one.
Does it oscillate "forever" or it relax to a macroscopical stationary state?

Ll.
 
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Not forever. Oscillations are a side effect of the compilcated mechanism of otherwise simple reaction - as long as there are reactants present reaction proceeds, at some point there is no more reactants - and it stops.
 
So from the differential equations point of view: the attractor set of the system is not really a limit cycle but a fixed point that corrispond at the equilibrium state.

Limite cycle arises when i consider an infinity of reactants, does it sound right?

Ll.
 
You are probably right, I am not used to this nomenclature.
 
So I know that electrons are fundamental, there's no 'material' that makes them up, it's like talking about a colour itself rather than a car or a flower. Now protons and neutrons and quarks and whatever other stuff is there fundamentally, I want someone to kind of teach me these, I have a lot of questions that books might not give the answer in the way I understand. Thanks
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