OUNT OF HEAT ABSORBED AND WORK DONE IN A PV DIAGRAM?

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paradiselost5
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Homework Statement



One mole of a dilute gas initially has a pressure equal to 1.00 atm, and a volume equal to 14.0 L. As the gas is slowly heated, the plot of its state on a PV diagram moves in a straight line to the final state. The gas now has a pressure equal to 2.00 atm, and a volume equal to 78.0 L.

(a) Find the work done by the gas.


(b) Find the heat absorbed by the gas.

Homework Equations





The Attempt at a Solution


I took the area under the PV curve which is a triangle... 64/2*101.325
 
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paradiselost5 said:


The Attempt at a Solution


I took the area under the PV curve which is a triangle... 64/2*101.325

Watch out: It is not a triangle. The work done by the gas is the area under the PV curve down to P=0.

ehild
 
In addition to what ehild points out, watch the units for volume. If you are using MKS units you have to convert litres to _________.

What is the relationship between work done, heat flow and change in internal energy? To find the heat flow, what other quantity do you have to find? (hint: what is the change in temperature?).

AM