Output power (torque-rotation) equivalent inertia

AI Thread Summary
The discussion focuses on calculating the equivalent moment of inertia related to output power in a drive train system. It introduces a new approach by associating output torque with equivalent inertia on the input side. The key equations involved include torque, kinetic energy, and power relationships. An attempt to derive the equivalent inertia expression reveals a need to eliminate rotational speeds, leading to a correction in the approach by using angular acceleration instead. The conversation emphasizes the importance of accurately representing the dynamics of the system in the calculations.
Adriano Marcato
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Homework Statement



A lot of people are familiar with equivalent inertia problems, where you have a drive train and inertia on different axis and you calculate the equivalent inertia on whichever shaft you want. This time I (try to) bring something new, trying to associate the output power to the equivalent moment of inertia on the input.

The system and the known information are shown bellow. Let's assume T1 is the driving torque and we want to get an equivalent inertia of the shafts AND the output torque T2
upload_2017-6-23_9-56-31.png

Homework Equations


T = I*ω
EK = (I*ω2)/2
P=T*ω
ω2*r1 = ω2*r2

The Attempt at a Solution


By means of equivalent kinetic energy, I've come to the following expression:
Ieq = I1 + I2*r1/r2 + T21/(ω2)2
I've been trying to eliminate the rotational speed in the last term.
 
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Torque = I*alpha {angular accel} not I*ω {angluar velocity}
 
Oh! indeed, I am sorry for the mistake. I meant to include a point above.
Please consider
Formula: T = I*α
Attempt at solution: Ieq = I1 + I2*r1/r2 + T21/(α2)2
Try to cancel the alphas on the last term.
 
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