Output Voltage of Feedback Amplifier is 14.85V

AI Thread Summary
The discussion revolves around calculating the output voltage of a feedback amplifier given an initial output of 15 V with 10% second harmonic distortion and an input signal of 15 mV. The open-loop gain (A) is established at 1000, with a feedback factor (beta) of 0.015. Participants clarify that the gain with feedback (Af) must be determined using the formula Af = A / (1 + beta * A). The confusion arises from the terminology used to describe the input and output voltages, but it is ultimately agreed that the output voltage with feedback can be calculated by adjusting the input voltage to account for feedback. The final output voltage is derived from amplifying the adjusted input signal by the established gain.
ranju
Messages
221
Reaction score
3

Homework Statement


An amplifier without feedback provides an output signal of 15 V with 10% second harmonic distortions when input signal signal is 15 mV. If 1.5% of the output is feedback to the input in a negative series shunt amplifier, what is output voltage?[/B]

Homework Equations


input signal (Vs) = 15mV , V0=15V , Af(gain with feedback) = V0/Vs[/B]

The Attempt at a Solution


I have got Af =1000 & feedback factor beta =0.015[/B]
 
Physics news on Phys.org
So, you have some working and an answer showing what is the output voltage with feedback?
 
Af=1000 is the open loop gain right. If that is so just calculate closed loop gain and multiply with the input .
 
lazyaditya said:
Af=1000 is the open loop gain right.
Af is the gain with feedback .. we can find A by Af=A/1+beta*A
but I am not getting how to find the output voltage with feedback..??
NascentOxygen said:
So, you have some working and an answer showing what is the output voltage with feedback?
we have to find the output voltage with feedback..!
 
15 V with 10% second harmonic distortions
Can you explain what this means?
 
15 V is the output voltage without feedback and 10% is the distortion D without feedback..!
 
I have got Af =1000 & feedback factor beta =0.015
The gain without feedback is 1000. So if you are using "Af" to denote gain with feedback, then Af is not 1000. We don't know what is the value of Af, you are required to determine Af.
 
  • Like
Likes lazyaditya
Not again.>! I am really sorry..Its my mistake once again..now I am not getting how to do it..!
 
Now that you know that A=15/15mV , A=1000 and you have beta=0.015 just calculate gain with feedback "Af" . Since input voltage has also been known (15 V), calculate output voltage by the equation you have given.
 
  • #10
This cannot be solved in this manner..! A is found when we are knowing the input voltage Vi but that is not given.>!
 
  • #11
ranju said:
An amplifier without feedback provides an output signal of 15 V with 10% second harmonic distortions when input signal signal is 15 mV.
Input signal is 15 mV and output you get without feedback is 15 V.
 
  • #12
This terminology difference is killing me..! ohkk..so finally its clear.. we are having without feedback: V0=15V and Vi=15mV..& hence A= 1000beta=0.015 , so we can find Af.. Now how we are going to find output voltage with feedback..??
 
  • #13
ranju said:
This terminology difference is killing me..! ohkk..so finally its clear.. we are having without feedback: V0=15V and Vi=15mV..& hence A= 1000beta=0.015 , so we can find Af.. Now how we are going to find output voltage with feedback..??
Output is 1000x the input, the same as before, there is no change there. But now the input to that amplifier, instead of being Vi, is made to be (Vi - βVo). So the amplifier amplifies this by 1000x
 
Back
Top