Parabolic Motion, *throw a ball with velocity at angle 45 6.2m above ground

AI Thread Summary
The discussion focuses on calculating various aspects of a ball's parabolic motion when thrown from a height of 6.2 meters at a velocity of 15 m/s and an angle of 45 degrees. Key calculations include determining the time of flight, horizontal range, maximum height, speed when the ball is 3 meters below the hill, and the angle at which it hits the ground. Participants suggest using uniform accelerated motion equations to derive these values, emphasizing the importance of separating vertical and horizontal components of the motion. The equations provided, such as v = u + at and R = (1/16)(initial velocity)^2 sin(2*angle), are essential for solving the problem. Overall, the discussion aims to guide the calculation of the ball's trajectory based on the given parameters.
Tommy22
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Jimmy tosses a ball with a velocity of 15m/s at 45degrees to the horizontal from a hill
6.2metres above ground.
Find:
-time of flight
-horizontal range
-maximum height
-speed of the ball when its 3m below the hill
-angle at which ball hits ground

Thx alot, ANY help would be appreciated.
 
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u should be able to develop a set of equations with your maths..
Umm... making use of uniform accelerated equations such as
v=u+at
s=(u+v)t/2
v^2-u^2 =2as
s=ut+1/2at^2
 
you could find range with R=1/16(Initial velocity)2sin(angle)cos(angle)
 
Tommy22 said:
Jimmy tosses a ball with a velocity of 15m/s at 45degrees to the horizontal from a hill

Split that into vertical and horizontal components(this is always constant).
Use the kinematics equations and consider vertical and horizontal motion.
 
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