# Parallel Plate Capacitance

1. Feb 13, 2009

### hellogirl88

A capacitor with capacitance of C = 8.5±1 μF has a potential difference of V = 4.5±0.4 Volts. What are the charge on the capacitor and the error in this value, in μC?

To find charge I just use Q = C*V correct? And how do I calculate the error?

Thank you!

2. Feb 13, 2009

### rock.freak667

For s=ab
$$\frac{\delta s }{s}= \frac{\delta a}{a} + \frac{\delta b}{b}$$

Where $\delta s$ is the error in s and similiarly for a and b.

3. Feb 13, 2009

### Delphi51

Another way to say that is that for multiplying and dividing, the % errors in quantities are added.