Parallel Plate Capacitor with Dielectric Connected to a Battery

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SUMMARY

The discussion focuses on analyzing a parallel plate capacitor that includes a dielectric slab connected to a battery. Participants suggest modeling the system as two capacitors in series: one with the dielectric and one in vacuum. The relevant equations include the Lorentz field equation E = Q/(A*ε0) and traditional capacitor equations for charge, voltage, and capacitance. The conversation emphasizes the importance of visual aids, such as diagrams, for better understanding the problem setup.

PREREQUISITES
  • Understanding of parallel plate capacitors
  • Familiarity with dielectric materials and their properties
  • Knowledge of capacitor equations and series combinations
  • Basic grasp of electric fields and displacement vectors
NEXT STEPS
  • Study the derivation of the electric field in capacitors with dielectrics
  • Learn about the relationship between displacement vector D and charge Q
  • Explore examples of capacitor calculations involving dielectrics
  • Review the concept of superposition in electric fields
USEFUL FOR

Students studying electromagnetism, electrical engineers, and anyone involved in capacitor design and analysis.

physconomic
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Homework Statement
Represent the system as the superposition of a polarized dielectric slab and a vacuum capacitor to find the total electric field in the capacitor in terms of Q and the polarisation P. Then find the relationship between the displacement vectorD and Q.
Relevant Equations
Lorentz field? E=q/(A*sigma0)
Not sure how to set this question up or how to get to the second half
 
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physconomic said:
Homework Statement:: Represent the system as the superposition of a polarized dielectric slab and a vacuum capacitor to find the total electric field in the capacitor in terms of Q and the polarisation P. Then find the relationship between the displacement vectorD and Q.
Relevant Equations:: Lorentz field? E=q/(A*sigma0)

Not sure how to set this question up or how to get to the second half
That's not really the full problem statement, and a diagram would help, but it sounds like you have a parallel plate capacitor with a dielectric slab filling some fraction of the separation distance?

If so, just model it as two capacitors in series -- one with the dielectric in it, and one with vacuum. Once you do that, just use the traditional equations for the charge on a capacitor versus voltage and capacitance, and the equation for the series combination of capacitors...
 
berkeman said:
That's not really the full problem statement, and a diagram would help, but it sounds like you have a parallel plate capacitor with a dielectric slab filling some fraction of the separation distance?

If so, just model it as two capacitors in series -- one with the dielectric in it, and one with vacuum. Once you do that, just use the traditional equations for the charge on a capacitor versus voltage and capacitance, and the equation for the series combination of capacitors...
Hi sorry yes it's just a standard parallel plate capacitor with a linear dielectric material filling the whole gap. Thank you though.
 
Okay, so can you start working the problem and post your work? You can also do a Google search for more information and examples -- this is a very common intro question about capacitor calculations...
 

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