Parallel Plate Capacitor with Dielectric Connected to a Battery

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To analyze a parallel plate capacitor with a dielectric connected to a battery, model the system as two capacitors in series: one with the dielectric and one in vacuum. Use the standard equations for charge, voltage, and capacitance to derive the total electric field in terms of charge (Q) and polarization (P). The relationship between the displacement vector (D) and charge can be established through the equations governing capacitors. A diagram would enhance understanding, but the problem can be approached using common capacitor calculation techniques. This method simplifies the analysis of the electric field and displacement in the system.
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Homework Statement
Represent the system as the superposition of a polarized dielectric slab and a vacuum capacitor to find the total electric field in the capacitor in terms of Q and the polarisation P. Then find the relationship between the displacement vectorD and Q.
Relevant Equations
Lorentz field? E=q/(A*sigma0)
Not sure how to set this question up or how to get to the second half
 
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physconomic said:
Homework Statement:: Represent the system as the superposition of a polarized dielectric slab and a vacuum capacitor to find the total electric field in the capacitor in terms of Q and the polarisation P. Then find the relationship between the displacement vectorD and Q.
Relevant Equations:: Lorentz field? E=q/(A*sigma0)

Not sure how to set this question up or how to get to the second half
That's not really the full problem statement, and a diagram would help, but it sounds like you have a parallel plate capacitor with a dielectric slab filling some fraction of the separation distance?

If so, just model it as two capacitors in series -- one with the dielectric in it, and one with vacuum. Once you do that, just use the traditional equations for the charge on a capacitor versus voltage and capacitance, and the equation for the series combination of capacitors...
 
berkeman said:
That's not really the full problem statement, and a diagram would help, but it sounds like you have a parallel plate capacitor with a dielectric slab filling some fraction of the separation distance?

If so, just model it as two capacitors in series -- one with the dielectric in it, and one with vacuum. Once you do that, just use the traditional equations for the charge on a capacitor versus voltage and capacitance, and the equation for the series combination of capacitors...
Hi sorry yes it's just a standard parallel plate capacitor with a linear dielectric material filling the whole gap. Thank you though.
 
Okay, so can you start working the problem and post your work? You can also do a Google search for more information and examples -- this is a very common intro question about capacitor calculations...
 
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