Parallel plate - uniform electric field help

AI Thread Summary
A parallel-plate uniform electric field of 325 N/C is set up, and an electron is released from rest, moving 3.2 cm to the left. The initial kinetic energy (KE) of the electron is zero, as it starts from rest. To find the final speed of the electron, the final kinetic energy must be calculated using the work done by the electric field on the electron. The discussion emphasizes applying physics principles to determine the final kinetic energy and subsequently the final speed. Understanding the relationship between electric field strength, charge, and distance is crucial for solving the problem.
alittlelost
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Homework Statement


A parallel-plate uniform electric field with a strength of 325 N/C is oriented as shown below. An electron (q = 1.6 × 10-19 C, m = 9.11 × 10-31 kg) is released (from rest) inside the field and moves 3.2 cm to the left. What is the final speed of the electron at the end of the 3.2-cm distance?


Homework Equations





The Attempt at a Solution


I did this:
Ek=.5mv2
Ek= .5(09.11 × 10-31)(0)2 and got 0... :/ any help would be appreciated.. I don't know where to start
 
Last edited:
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well you've done right so far. you have got the initial KE of the electron, which is zero. For now, try to find the final KE (and then afterwards, you can get final speed). So, in this situation, how can you find the final KE? What physics principles can you apply?
 

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