Parallel Plates - Electron Liberation

AI Thread Summary
An electron is liberated from two parallel plates separated by 5mm, with a potential difference of 1000V. The initial calculations yield an acceleration of 3.513 x 10^16 m/s² and a time of 5.335 x 10^-10 seconds for the electron to reach the upper plate. Another contributor suggests using relativistic mass and differentiation to find the time, estimating it at 4.5 x 10^-11 seconds. The discussion highlights the importance of understanding both classical and relativistic approaches in solving the problem. The conversation emphasizes the need for clarity in applying physics equations to arrive at accurate results.
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Homework Statement


Hello, I wonder if anyone could check my answer to this problem.

Thanks in advance

An electron is liberated from the lower of two parallel plates separated by a distance of 5mm. The upper plate has a p.d. of 1000v relative to the lower plate. How long does it it take for the electron to reach to upper plate.

Homework Equations


f=ma, f=qe, e=v/d

The Attempt at a Solution


I said F=ma=QE therefore QE=ma and since E=V/d=1000/0.005=2x105

a=3.513x1016m/s2!

Then using s=ut+1/2at2, t=5.335x10-10s.

Thanks again for any help

Mike
 
Last edited:
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i would take

ma = relativistic mass * dv/dt = qE

solve for v and find time taken
 
Hello, thanks for your response.

Is that differentiation? Not too sure about how to do that.

Any chance you could get an answer from your method and compare it to mine.

Thanks again,

Mike
 
4.5*10^-11 s

try it, its really simple
 
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