What is the missing value in this parallel RC circuit problem?

AI Thread Summary
In the discussion about the parallel RC circuit problem, the user is struggling to find the voltage across one capacitor (Vc1), which they calculated as 31.8V at an angle of -90 degrees, while the expected answer is 5V at 0 degrees. The circuit consists of two equal capacitors and resistors connected to a 10V source at a frequency of 5kHz. A participant explains that the capacitors form a voltage divider, resulting in each capacitor receiving half of the source voltage, which is why Vc1 should be 5V. The conversation highlights the importance of understanding voltage division in parallel circuits to arrive at the correct values.
DethRose
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Parallel RC Circuit Problem!

Hey I've been working on this circuit for hours and can't figure out 1 value.
This is exactly what was given to me on the page so i have no other information lol.

All that was written was:

find the values of Zt,It,I1,I2,Vc1

Ive found all the other values which are

Zt = 1.2 k angle -10.93
It = 8.28 mA angle 10.93
I1 = 8.13 mA angle 0
I2 = 1.57 mA angle 90
Vc1 i get 31.8 v angle -90 but the given answer is 5v and 0

An explanation y it is that value would be appreciated


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l l l
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l 550 ohm resistor .01 microFarad Capacitor
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10V angle 0 l l
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l 680 ohm resistor .01 microFarad Capacitor
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l frequency=5KHZ l l
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l----------------------l-------------------l
 
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dumwit atleast type what you are asking properly
 
Well personally I would NOT call you dumbwit or any other name , but I am afraid he is correct in that I am not sure how anyone can understand your question
Ray
 
so where's the micky mouse cartoon i was promised1
 
Hi DethRose,
The capacitors are equal in size and form a simple voltage divider across the source. Regardless of the current through the capacitors, the voltage across each capacitor must logically be half of the source voltage ... 5v @ 0degrees.

V_{C1}=V_s\frac{Z_{C1}}{Z_{C1}+Z_{C2}}<br /> =V_s\frac{j\omega C1}{j\omega C1+j\omega C2}<br /> =V_s\frac{C1}{C1+C2}=V_s\frac{C1}{2C1}=\frac{V_s}{2}

(it seems your other respondents have no imagination)
 
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