Parametric Equations: Get Started Now

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SUMMARY

The discussion focuses on understanding the motion of a pen attached to the rim of a rolling wheel, specifically in the context of parametric equations. The wheel is confirmed to be rolling along the x-axis, producing a cycloid, although the pen's position is in the interior of the wheel. The motion can be decomposed into two components: the motion of the wheel and the motion of the pen around the wheel's hub. The mathematical representation involves the vector equation 'OP = OC + CP', where the coordinates of the center and pen are expressed in terms of the wheel's radius and angle.

PREREQUISITES
  • Understanding of parametric equations
  • Knowledge of cycloid generation
  • Familiarity with vector notation
  • Basic concepts of polar coordinates
NEXT STEPS
  • Study the derivation of cycloid equations
  • Learn about vector decomposition in motion analysis
  • Explore polar coordinates and their applications in parametric equations
  • Investigate the relationship between rolling motion and parametric curves
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Students and educators in mathematics, particularly those focused on calculus and geometry, as well as engineers and physicists interested in motion analysis and parametric modeling.

halvizo1031
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Can someone help me get started on number one please?
 

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It's not clear to me whether the wheel is rolling along the x-axis, or rotating in place. Which is it?
 
Well that's where I'm stuck. Since it says "rim of a wheel", my only guess is that it is moving along the x-axis. If this is the case, then it produces a cycloid right?
 
Strictly speaking, a cycloid is produced only when the pen lies on the rim of the rolling wheel; our pen is in the interior.

If you suppose the wheel to be rolling, then decompose the motion of the pen into two parts, the motion of the wheel, and the motion of the pen about the wheel's hub.
 
wow that's toughy
 
If P = (x,y) and if you call the center of the circle C you know that

\vec{OP}=\vec{OC} + \vec{CP}

Since the wheel isn't slipping, you know the x coordinate of the center is the same as the arc of the wheel a\theta and the y coordinate is a. So you can begin with

\langle x,y\rangle=\langle a\theta, a\rangle + \vec{CP}

Now figure out the components of CP in terms of \theta. It isn't difficult, especially if you write them in terms of the standard polar angle at the center C and use that go get it in terms of \theta.
 

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